Answer:
Option D
Explanation:
When A covers the distance of 1760 m, B covers only $1760-44$ =1716 m
In 1320 m race, B can beat C by 30 m.
If B runs 1320 m, C runs $1320-30$ =1290 m
If B runs 1716 m, C runs $=\frac{(1290\times 1716)}{1320}$ = 1677 m
$A:B:C$ $=1760:1716:1677$
Hence A will beat C by $1760-1677$ $=83$ m in 1760 m race
i.e. $\frac{83}{2}$ $=41\frac{1}{2}$ m in 880 race.